(3x+13)+(2x+19)=(6x+11)

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Solution for (3x+13)+(2x+19)=(6x+11) equation: 



(3x+13)+(2x+19)=(6x+11)

We move all terms to the left:

(3x+13)+(2x+19)-((6x+11))=0

We get rid of parentheses

3x+2x-((6x+11))+13+19=0



We calculate terms in parentheses: -((6x+11)), so:

(6x+11)

We get rid of parentheses

6x+11

Back to the equation:

-(6x+11)



We add all the numbers together, and all the variables

5x-(6x+11)+32=0

We get rid of parentheses

5x-6x-11+32=0

We add all the numbers together, and all the variables

-1x+21=0

We move all terms containing x to the left, all other terms to the right

-x=-21

x=-21/-1

x=+21

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