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0=-x(x-25)
We move all terms to the left:
0-(-x(x-25))=0
We add all the numbers together, and all the variables
-(-x(x-25))=0
We calculate terms in parentheses: -(-x(x-25)), so:We get rid of parentheses
-x(x-25)
We multiply parentheses
-x^2+25x
We add all the numbers together, and all the variables
-1x^2+25x
Back to the equation:
-(-1x^2+25x)
1x^2-25x=0
We add all the numbers together, and all the variables
x^2-25x=0
a = 1; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·1·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*1}=\frac{50}{2} =25 $
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