5(v+2)+(v+5)=1

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Solution for 5(v+2)+(v+5)=1 equation: 



5(v+2)+(v+5)=1

We move all terms to the left:

5(v+2)+(v+5)-(1)=0

We multiply parentheses

5v+(v+5)+10-1=0

We get rid of parentheses

5v+v+5+10-1=0

We add all the numbers together, and all the variables

6v+14=0

We move all terms containing v to the left, all other terms to the right

6v=-14

v=-14/6

v=-2+1/3

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