5(y+8)=2(y+1)=0

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Solution for 5(y+8)=2(y+1)=0 equation: 



5(y+8)=2(y+1)=0

We move all terms to the left:

5(y+8)-(2(y+1))=0

We multiply parentheses

5y-(2(y+1))+40=0



We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)



We get rid of parentheses

5y-2y-2+40=0

We add all the numbers together, and all the variables

3y+38=0

We move all terms containing y to the left, all other terms to the right

3y=-38

y=-38/3

y=-12+2/3

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