0=(-x-2)(-2x-3)

Solution for 0=(-x-2)(-2x-3) equation:

0=(-x-2)(-2x-3)

We move all terms to the left:

0-((-x-2)(-2x-3))=0

We add all the numbers together, and all the variables

-((-1x-2)(-2x-3))+0=0

We add all the numbers together, and all the variables

-((-1x-2)(-2x-3))=0

We multiply parentheses ..

-((+2x^2+3x+4x+6))=0


We calculate terms in parentheses: -((+2x^2+3x+4x+6)), so:

(+2x^2+3x+4x+6)

We get rid of parentheses

2x^2+3x+4x+6

We add all the numbers together, and all the variables

2x^2+7x+6

Back to the equation:

-(2x^2+7x+6)


We get rid of parentheses

-2x^2-7x-6=0

a = -2; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·(-2)·(-6)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*-2}=\frac{6}{-4}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*-2}=\frac{8}{-4}
=-2
$