0(x)=(-x-2)(-2x-3)

Solution for 0(x)=(-x-2)(-2x-3) equation:

0(x)=(-x-2)(-2x-3)

We move all terms to the left:

0(x)-((-x-2)(-2x-3))=0

We add all the numbers together, and all the variables

0x-((-1x-2)(-2x-3))=0

We add all the numbers together, and all the variables

x-((-1x-2)(-2x-3))=0

We multiply parentheses ..

-((+2x^2+3x+4x+6))+x=0


We calculate terms in parentheses: -((+2x^2+3x+4x+6)), so:

(+2x^2+3x+4x+6)

We get rid of parentheses

2x^2+3x+4x+6

We add all the numbers together, and all the variables

2x^2+7x+6

Back to the equation:

-(2x^2+7x+6)


We add all the numbers together, and all the variables

x-(2x^2+7x+6)=0

We get rid of parentheses

-2x^2+x-7x-6=0

We add all the numbers together, and all the variables

-2x^2-6x-6=0

a = -2; b = -6; c = -6;
Δ = b2-4ac
Δ = -62-4·(-2)·(-6)
Δ = -12
Delta is less than zero, so there is no solution for the equation