(3/4)(16x-4)=21

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Solution for (3/4)(16x-4)=21 equation: 



(3/4)(16x-4)=21

We move all terms to the left:

(3/4)(16x-4)-(21)=0



Domain of the equation: 4)(16x-4)!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)(16x-4)-21=0

We multiply parentheses ..

(+48x^2+3/4*-4)-21=0

We multiply all the terms by the denominator


(+48x^2+3-21*4*-4)=0

We get rid of parentheses

48x^2+3-4-21*4*=0

We add all the numbers together, and all the variables

48x^2=0

a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{96}=0$

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