0.9(4y-2)=0.5(3y-4)+4.4

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Solution for 0.9(4y-2)=0.5(3y-4)+4.4 equation: 



0.9(4y-2)=0.5(3y-4)+4.4

We move all terms to the left:

0.9(4y-2)-(0.5(3y-4)+4.4)=0

We multiply parentheses

3.6y-(0.5(3y-4)+4.4)-1.8=0



We calculate terms in parentheses: -(0.5(3y-4)+4.4), so:

0.5(3y-4)+4.4

We multiply parentheses

1.5y-2+4.4

We add all the numbers together, and all the variables

1.5y+2.4

Back to the equation:

-(1.5y+2.4)



We get rid of parentheses

3.6y-1.5y-2.4-1.8=0

We add all the numbers together, and all the variables

2.1y-4.2=0

We move all terms containing y to the left, all other terms to the right

2.1y=4.2

y=4.2/2.1

y=2

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