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3x-9=1/x+2
We move all terms to the left:
3x-9-(1/x+2)=0
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
3x-1/x-2-9=0
We multiply all the terms by the denominator
3x*x-2*x-9*x-1=0
We add all the numbers together, and all the variables
-11x+3x*x-1=0
Wy multiply elements
3x^2-11x-1=0
a = 3; b = -11; c = -1;
Δ = b2-4ac
Δ = -112-4·3·(-1)
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{133}}{2*3}=\frac{11-\sqrt{133}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{133}}{2*3}=\frac{11+\sqrt{133}}{6} $
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