0.2(40)+0.25x=0.1(40)+0/3x

Solution for 0.2(40)+0.25x=0.1(40)+0/3x equation:

0.2(40)+0.25x=0.1(40)+0/3x

We move all terms to the left:

0.2(40)+0.25x-(0.1(40)+0/3x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

0.25x-(0/3x+0.14)+0.240=0

We add all the numbers together, and all the variables

0.25x-(0/3x+0.14)+0.24=0

We get rid of parentheses

0.25x-0/3x-0.14+0.24=0

We multiply all the terms by the denominator


(0.25x)*3x-(0.14)*3x+(0.24)*3x-0=0

We add all the numbers together, and all the variables

(+0.25x)*3x-(0.14)*3x+(0.24)*3x-0=0

We add all the numbers together, and all the variables

(+0.25x)*3x-(0.14)*3x+(0.24)*3x=0

We multiply parentheses

0x^2-0.42x+0.72x=0

We add all the numbers together, and all the variables

x^2+0.3x=0

a = 1; b = 0.3; c = 0;
Δ = b2-4ac
Δ = 0.32-4·1·0
Δ = 0.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3)-\sqrt{0.09}}{2*1}=\frac{-0.3-\sqrt{0.09}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3)+\sqrt{0.09}}{2*1}=\frac{-0.3+\sqrt{0.09}}{2}
$