0.12(y-7)+0.02y=0.04-0.03(30)

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Solution for 0.12(y-7)+0.02y=0.04-0.03(30) equation: 



0.12(y-7)+0.02y=0.04-0.03(30)

We move all terms to the left:

0.12(y-7)+0.02y-(0.04-0.03(30))=0

We add all the numbers together, and all the variables

0.12(y-7)+0.02y-(0.007)=0

We add all the numbers together, and all the variables

0.02y+0.12(y-7)-0.007=0

We multiply parentheses

0.02y+0.12y-0.84-0.007=0

We add all the numbers together, and all the variables

0.14y-0.847=0

We move all terms containing y to the left, all other terms to the right

0.14y=0.847

y=0.847/0.14

y=6+0.0069999999999999/0.14

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