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-12x(-13x)=256
We move all terms to the left:
-12x(-13x)-(256)=0
We multiply parentheses
156x^2-256=0
a = 156; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·156·(-256)
Δ = 159744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{159744}=\sqrt{4096*39}=\sqrt{4096}*\sqrt{39}=64\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{39}}{2*156}=\frac{0-64\sqrt{39}}{312} =-\frac{64\sqrt{39}}{312} =-\frac{8\sqrt{39}}{39} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{39}}{2*156}=\frac{0+64\sqrt{39}}{312} =\frac{64\sqrt{39}}{312} =\frac{8\sqrt{39}}{39} $
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