0.04z(2)=0.36

Solution for 0.04z(2)=0.36 equation:

0.04z(2)=0.36

We move all terms to the left:

0.04z(2)-(0.36)=0

We add all the numbers together, and all the variables

0.04z^2-0.36=0

a = 0.04; b = 0; c = -0.36;
Δ = b2-4ac
Δ = 02-4·0.04·(-0.36)
Δ = 0.0576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0576}}{2*0.04}=\frac{0-\sqrt{0.0576}}{0.08}
=-\frac{\sqrt{}}{0.08}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0576}}{2*0.04}=\frac{0+\sqrt{0.0576}}{0.08}
=\frac{\sqrt{}}{0.08}
$