2(2t-12)=3(t-10)

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Solution for 2(2t-12)=3(t-10) equation: 



2(2t-12)=3(t-10)

We move all terms to the left:

2(2t-12)-(3(t-10))=0

We multiply parentheses

4t-(3(t-10))-24=0



We calculate terms in parentheses: -(3(t-10)), so:

3(t-10)

We multiply parentheses

3t-30

Back to the equation:

-(3t-30)



We get rid of parentheses

4t-3t+30-24=0

We add all the numbers together, and all the variables

t+6=0

We move all terms containing t to the left, all other terms to the right

t=-6

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