3(7d-4)=5(4d+4)

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Solution for 3(7d-4)=5(4d+4) equation: 



3(7d-4)=5(4d+4)

We move all terms to the left:

3(7d-4)-(5(4d+4))=0

We multiply parentheses

21d-(5(4d+4))-12=0



We calculate terms in parentheses: -(5(4d+4)), so:

5(4d+4)

We multiply parentheses

20d+20

Back to the equation:

-(20d+20)



We get rid of parentheses

21d-20d-20-12=0

We add all the numbers together, and all the variables

d-32=0

We move all terms containing d to the left, all other terms to the right

d=32

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