0.03(7t+3)=0.21(t+1)-0.12

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Solution for 0.03(7t+3)=0.21(t+1)-0.12 equation: 



0.03(7t+3)=0.21(t+1)-0.12

We move all terms to the left:

0.03(7t+3)-(0.21(t+1)-0.12)=0

We multiply parentheses

0.21t-(0.21(t+1)-0.12)+0.09=0



We calculate terms in parentheses: -(0.21(t+1)-0.12), so:

0.21(t+1)-0.12

We multiply parentheses

0.21t+0.21-0.12

We add all the numbers together, and all the variables

0.21t+0.09

Back to the equation:

-(0.21t+0.09)



We get rid of parentheses

0.21t-0.21t-0.09+0.09=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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