5(f-2)+f=6(f+3-4f

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Solution for 5(f-2)+f=6(f+3-4f equation: 



5(f-2)+f=6(f+3-4f

We move all terms to the left:

5(f-2)+f-(6(f+3-4f)=0

We add all the numbers together, and all the variables

5(f-2)+f-(6(-3f+3)=0

We add all the numbers together, and all the variables

f+5(f-2)-(6(-3f+3)=0

We multiply parentheses

f+5f-(6(-3f+3)-10=0

We add all the numbers together, and all the variables

6f-(6(-3f+3)-10=0

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