26=(x+3)+(2x-6)+(x+3)+(2x-6)

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Solution for 26=(x+3)+(2x-6)+(x+3)+(2x-6) equation: 



26=(x+3)+(2x-6)+(x+3)+(2x-6)

We move all terms to the left:

26-((x+3)+(2x-6)+(x+3)+(2x-6))=0



We calculate terms in parentheses: -((x+3)+(2x-6)+(x+3)+(2x-6)), so:

(x+3)+(2x-6)+(x+3)+(2x-6)

We get rid of parentheses

x+2x+x+2x+3-6+3-6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

-6x+6+26=0

We add all the numbers together, and all the variables

-6x+32=0

We move all terms containing x to the left, all other terms to the right

-6x=-32

x=-32/-6

x=5+1/3

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