0.02x+0.2(x-2)=0.12

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Solution for 0.02x+0.2(x-2)=0.12 equation: 



0.02x+0.2(x-2)=0.12

We move all terms to the left:

0.02x+0.2(x-2)-(0.12)=0

We add all the numbers together, and all the variables

0.02x+0.2(x-2)-0.12=0

We multiply parentheses

0.02x+0.2x-0.4-0.12=0

We add all the numbers together, and all the variables

0.22x-0.52=0

We move all terms containing x to the left, all other terms to the right

0.22x=0.52

x=0.52/0.22

x=2+0.08/0.22

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