3(6z+1)=-(-20z+11)

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Solution for 3(6z+1)=-(-20z+11) equation: 



3(6z+1)=-(-20z+11)

We move all terms to the left:

3(6z+1)-(-(-20z+11))=0

We multiply parentheses

18z-(-(-20z+11))+3=0



We calculate terms in parentheses: -(-(-20z+11)), so:

-(-20z+11)

We get rid of parentheses

20z-11

Back to the equation:

-(20z-11)



We get rid of parentheses

18z-20z+11+3=0

We add all the numbers together, and all the variables

-2z+14=0

We move all terms containing z to the left, all other terms to the right

-2z=-14

z=-14/-2

z=+7

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