0,7(6y-5)=0,4(y-3)-0,5

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Solution for 0,7(6y-5)=0,4(y-3)-0,5 equation: 



0.7(6y-5)=0.4(y-3)-0.5

We move all terms to the left:

0.7(6y-5)-(0.4(y-3)-0.5)=0

We multiply parentheses

4.2y-(0.4(y-3)-0.5)-3.5=0



We calculate terms in parentheses: -(0.4(y-3)-0.5), so:

0.4(y-3)-0.5

We multiply parentheses

0.4y-1.2-0.5

We add all the numbers together, and all the variables

0.4y-1.7

Back to the equation:

-(0.4y-1.7)



We get rid of parentheses

4.2y-0.4y+1.7-3.5=0

We add all the numbers together, and all the variables

3.8y-1.8=0

We move all terms containing y to the left, all other terms to the right

3.8y=1.8

y=1.8/3.8

y=1/2.1111111111111

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