4(2y-7)=64+12

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Solution for 4(2y-7)=64+12 equation: 



4(2y-7)=64+12

We move all terms to the left:

4(2y-7)-(64+12)=0

We add all the numbers together, and all the variables

4(2y-7)-76=0

We multiply parentheses

8y-28-76=0

We add all the numbers together, and all the variables

8y-104=0

We move all terms containing y to the left, all other terms to the right

8y=104

y=104/8

y=13

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