6-4(2-5x)=6-4(-3x)=6+12x

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Solution for 6-4(2-5x)=6-4(-3x)=6+12x equation: 



6-4(2-5x)=6-4(-3x)=6+12x

We move all terms to the left:

6-4(2-5x)-(6-4(-3x))=0

We add all the numbers together, and all the variables

-4(-5x+2)-(6-4(-3x))+6=0

We multiply parentheses

20x-(6-4(-3x))-8+6=0



We calculate terms in parentheses: -(6-4(-3x)), so:

6-4(-3x)

determiningTheFunctionDomain
-4(-3x)+6

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We add all the numbers together, and all the variables

20x-(12x+6)-2=0

We get rid of parentheses

20x-12x-6-2=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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