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0.25x^2-1.21=0
a = 0.25; b = 0; c = -1.21;
Δ = b2-4ac
Δ = 02-4·0.25·(-1.21)
Δ = 1.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.21}}{2*0.25}=\frac{0-\sqrt{1.21}}{0.5} =-\frac{\sqrt{}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.21}}{2*0.25}=\frac{0+\sqrt{1.21}}{0.5} =\frac{\sqrt{}}{0.5} $
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