2(v+9)=-3(4v-5)+8v

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Solution for 2(v+9)=-3(4v-5)+8v equation: 



2(v+9)=-3(4v-5)+8v

We move all terms to the left:

2(v+9)-(-3(4v-5)+8v)=0

We multiply parentheses

2v-(-3(4v-5)+8v)+18=0



We calculate terms in parentheses: -(-3(4v-5)+8v), so:

-3(4v-5)+8v

We add all the numbers together, and all the variables

8v-3(4v-5)

We multiply parentheses

8v-12v+15

We add all the numbers together, and all the variables

-4v+15

Back to the equation:

-(-4v+15)



We get rid of parentheses

2v+4v-15+18=0

We add all the numbers together, and all the variables

6v+3=0

We move all terms containing v to the left, all other terms to the right

6v=-3

v=-3/6

v=-1/2

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