-2(v+1)=4v-3+2(2v+8)

Solution for -2(v+1)=4v-3+2(2v+8) equation:

-2(v+1)=4v-3+2(2v+8)

We move all terms to the left:

-2(v+1)-(4v-3+2(2v+8))=0

We multiply parentheses

-2v-(4v-3+2(2v+8))-2=0


We calculate terms in parentheses: -(4v-3+2(2v+8)), so:

4v-3+2(2v+8)

determiningTheFunctionDomain
4v+2(2v+8)-3

We multiply parentheses

4v+4v+16-3

We add all the numbers together, and all the variables

8v+13

Back to the equation:

-(8v+13)


We get rid of parentheses

-2v-8v-13-2=0

We add all the numbers together, and all the variables

-10v-15=0

We move all terms containing v to the left, all other terms to the right

-10v=15

v=15/-10

v=-1+1/2