.4x-2(1+3x)=5-3(x+2)

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Solution for .4x-2(1+3x)=5-3(x+2) equation:



.4x-2(1+3x)=5-3(x+2)
We move all terms to the left:
.4x-2(1+3x)-(5-3(x+2))=0
We add all the numbers together, and all the variables
.4x-2(3x+1)-(5-3(x+2))=0
We multiply parentheses
.4x-6x-(5-3(x+2))-2=0
We calculate terms in parentheses: -(5-3(x+2)), so:
5-3(x+2)
determiningTheFunctionDomain -3(x+2)+5
We multiply parentheses
-3x-6+5
We add all the numbers together, and all the variables
-3x-1
Back to the equation:
-(-3x-1)
We add all the numbers together, and all the variables
-5.6x-(-3x-1)-2=0
We get rid of parentheses
-5.6x+3x+1-2=0
We add all the numbers together, and all the variables
-2.6x-1=0
We move all terms containing x to the left, all other terms to the right
-2.6x=1
x=1/-2.6
x=-1/2.6

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