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0.04x^2-0.4x+1=0
a = 0.04; b = -0.4; c = +1;
Δ = b2-4ac
Δ = -0.42-4·0.04·1
Δ = 2.77555756156E-17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.4)-\sqrt{2.77555756156E-17}}{2*0.04}=\frac{0.4-\sqrt{2.77555756156E-17}}{0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.4)+\sqrt{2.77555756156E-17}}{2*0.04}=\frac{0.4+\sqrt{2.77555756156E-17}}{0.08} $
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