3(2x+5)+1=4x+28

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Solution for 3(2x+5)+1=4x+28 equation: 



3(2x+5)+1=4x+28

We move all terms to the left:

3(2x+5)+1-(4x+28)=0

We multiply parentheses

6x-(4x+28)+15+1=0

We get rid of parentheses

6x-4x-28+15+1=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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