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4x-30=2(4x+1)x=
We move all terms to the left:
4x-30-(2(4x+1)x)=0
We calculate terms in parentheses: -(2(4x+1)x), so:We get rid of parentheses
2(4x+1)x
We multiply parentheses
8x^2+2x
Back to the equation:
-(8x^2+2x)
-8x^2+4x-2x-30=0
We add all the numbers together, and all the variables
-8x^2+2x-30=0
a = -8; b = 2; c = -30;
Δ = b2-4ac
Δ = 22-4·(-8)·(-30)
Δ = -956
Delta is less than zero, so there is no solution for the equation
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