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0.04x^2-2.4x+27=0
a = 0.04; b = -2.4; c = +27;
Δ = b2-4ac
Δ = -2.42-4·0.04·27
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{1.44}}{2*0.04}=\frac{2.4-\sqrt{1.44}}{0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{1.44}}{2*0.04}=\frac{2.4+\sqrt{1.44}}{0.08} $
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