.14(y-3)+.02y=0.06y-0.07(10)

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Solution for .14(y-3)+.02y=0.06y-0.07(10) equation:



.14(y-3)+.02y=0.06y-0.07(10)
We move all terms to the left:
.14(y-3)+.02y-(0.06y-0.07(10))=0
We add all the numbers together, and all the variables
.14(y-3)+.02y-(0.06y-0.071)=0
We add all the numbers together, and all the variables
.02y+.14(y-3)-(0.06y-0.071)=0
We multiply parentheses
.02y+0.14y-(0.06y-0.071)-0.42=0
We get rid of parentheses
.02y+0.14y-0.06y+0.071-0.42=0
We add all the numbers together, and all the variables
0.1y-0.349=0
We move all terms containing y to the left, all other terms to the right
0.1y=0.349
y=0.349/0.1
y=3+0.049/0.1

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