120c+160=4c+20+c

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Solution for 120c+160=4c+20+c equation: 



120c+160=4c+20+c

We move all terms to the left:

120c+160-(4c+20+c)=0

We add all the numbers together, and all the variables

120c-(5c+20)+160=0

We get rid of parentheses

120c-5c-20+160=0

We add all the numbers together, and all the variables

115c+140=0

We move all terms containing c to the left, all other terms to the right

115c=-140

c=-140/115

c=-1+5/23

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