-9(k-5)+9=3+3(k+13)

Solution for -9(k-5)+9=3+3(k+13) equation:

-9(k-5)+9=3+3(k+13)

We move all terms to the left:

-9(k-5)+9-(3+3(k+13))=0

We multiply parentheses

-9k-(3+3(k+13))+45+9=0


We calculate terms in parentheses: -(3+3(k+13)), so:

3+3(k+13)

determiningTheFunctionDomain
3(k+13)+3

We multiply parentheses

3k+39+3

We add all the numbers together, and all the variables

3k+42

Back to the equation:

-(3k+42)


We add all the numbers together, and all the variables

-9k-(3k+42)+54=0

We get rid of parentheses

-9k-3k-42+54=0

We add all the numbers together, and all the variables

-12k+12=0

We move all terms containing k to the left, all other terms to the right

-12k=-12

k=-12/-12

k=1