6-7(a+1)=-3(2-a)0/9

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Solution for 6-7(a+1)=-3(2-a)0/9 equation:



6-7(a+1)=-3(2-a)0/9
We move all terms to the left:
6-7(a+1)-(-3(2-a)0/9)=0
We add all the numbers together, and all the variables
-7(a+1)-(-3(-1a+2)0/9)+6=0
We multiply parentheses
-7a-(-3(-1a+2)0/9)-7+6=0
We multiply all the terms by the denominator
-7a*9)-(-3(-1a+2)0-7*9)+6*9)=0
We add all the numbers together, and all the variables
-7a*9)-(-3(-1a+2)0=0
We multiply parentheses
-7a*9)-(+3a-6=0
Wy multiply elements
-63a^2+3a-6=0
a = -63; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·(-63)·(-6)
Δ = -1503
Delta is less than zero, so there is no solution for the equation

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