11x-3(2x-1)=12(x-2)+13

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Solution for 11x-3(2x-1)=12(x-2)+13 equation: 



11x-3(2x-1)=12(x-2)+13

We move all terms to the left:

11x-3(2x-1)-(12(x-2)+13)=0

We multiply parentheses

11x-6x-(12(x-2)+13)+3=0



We calculate terms in parentheses: -(12(x-2)+13), so:

12(x-2)+13

We multiply parentheses

12x-24+13

We add all the numbers together, and all the variables

12x-11

Back to the equation:

-(12x-11)



We add all the numbers together, and all the variables

5x-(12x-11)+3=0

We get rid of parentheses

5x-12x+11+3=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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