-8y+41=3(y-1)

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Solution for -8y+41=3(y-1) equation: 



-8y+41=3(y-1)

We move all terms to the left:

-8y+41-(3(y-1))=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

-8y-3y+3+41=0

We add all the numbers together, and all the variables

-11y+44=0

We move all terms containing y to the left, all other terms to the right

-11y=-44

y=-44/-11

y=+4

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