7y-2(y-7)=12y-(8y-10)

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Solution for 7y-2(y-7)=12y-(8y-10) equation: 



7y-2(y-7)=12y-(8y-10)

We move all terms to the left:

7y-2(y-7)-(12y-(8y-10))=0

We multiply parentheses

7y-2y-(12y-(8y-10))+14=0



We calculate terms in parentheses: -(12y-(8y-10)), so:

12y-(8y-10)

We get rid of parentheses

12y-8y+10

We add all the numbers together, and all the variables

4y+10

Back to the equation:

-(4y+10)



We add all the numbers together, and all the variables

5y-(4y+10)+14=0

We get rid of parentheses

5y-4y-10+14=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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