(y+2)*(y+2)=7y

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Solution for (y+2)*(y+2)=7y equation: 



(y+2)(y+2)=7y

We move all terms to the left:

(y+2)(y+2)-(7y)=0

We add all the numbers together, and all the variables

-7y+(y+2)(y+2)=0

We multiply parentheses ..

(+y^2+2y+2y+4)-7y=0

We get rid of parentheses

y^2+2y+2y-7y+4=0

We add all the numbers together, and all the variables

y^2-3y+4=0

a = 1; b = -3; c = +4;
Δ = b2-4ac
Δ = -32-4·1·4
Δ = -7
Delta is less than zero, so there is no solution for the equation

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