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-8(5x+5)+9x(10x+9)=20
We move all terms to the left:
-8(5x+5)+9x(10x+9)-(20)=0
We multiply parentheses
90x^2-40x+81x-40-20=0
We add all the numbers together, and all the variables
90x^2+41x-60=0
a = 90; b = 41; c = -60;
Δ = b2-4ac
Δ = 412-4·90·(-60)
Δ = 23281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{23281}}{2*90}=\frac{-41-\sqrt{23281}}{180} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{23281}}{2*90}=\frac{-41+\sqrt{23281}}{180} $
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