4(2x-7)-8(5-x)=3(2x+4)-5(+7)

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Solution for 4(2x-7)-8(5-x)=3(2x+4)-5(+7) equation: 



4(2x-7)-8(5-x)=3(2x+4)-5(+7)

We move all terms to the left:

4(2x-7)-8(5-x)-(3(2x+4)-5(+7))=0

We add all the numbers together, and all the variables

4(2x-7)-8(-1x+5)-(3(2x+4)-57)=0

We multiply parentheses

8x+8x-(3(2x+4)-57)-28-40=0



We calculate terms in parentheses: -(3(2x+4)-57), so:

3(2x+4)-57

We multiply parentheses

6x+12-57

We add all the numbers together, and all the variables

6x-45

Back to the equation:

-(6x-45)



We add all the numbers together, and all the variables

16x-(6x-45)-68=0

We get rid of parentheses

16x-6x+45-68=0

We add all the numbers together, and all the variables

10x-23=0

We move all terms containing x to the left, all other terms to the right

10x=23

x=23/10

x=2+3/10

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