y-y-1/2=1-(y-2)/3

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Solution for y-y-1/2=1-(y-2)/3 equation: 



y-y-1/2=1-(y-2)/3

We move all terms to the left:

y-y-1/2-(1-(y-2)/3)=0

We add all the numbers together, and all the variables

-(1-(y-2)/3)-1/2=0

We calculate fractions


(-(1-(y-2)*2)/()+()/()=0



We calculate terms in parentheses: +(-(1-(y-2)*2)/()+()/(), so:

-(1-(y-2)*2)/()+()/(

We add all the numbers together, and all the variables

-(1-(y-2)*2)/()+1

We multiply all the terms by the denominator


-(1-(y-2)*2)+1*()



We calculate terms in parentheses: -(1-(y-2)*2), so:

1-(y-2)*2

determiningTheFunctionDomain
-(y-2)*2+1

We multiply parentheses

-2y+4+1

We add all the numbers together, and all the variables

-2y+5

Back to the equation:

-(-2y+5)



We add all the numbers together, and all the variables

-(-2y+5)

We get rid of parentheses

2y-5

Back to the equation:

+(2y-5)



We get rid of parentheses

2y-5=0

We move all terms containing y to the left, all other terms to the right

2y=5

y=5/2

y=2+1/2

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