-7r-8(1-3r)=40+r

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Solution for -7r-8(1-3r)=40+r equation: 



-7r-8(1-3r)=40+r

We move all terms to the left:

-7r-8(1-3r)-(40+r)=0

We add all the numbers together, and all the variables

-7r-8(-3r+1)-(r+40)=0

We multiply parentheses

-7r+24r-(r+40)-8=0

We get rid of parentheses

-7r+24r-r-40-8=0

We add all the numbers together, and all the variables

16r-48=0

We move all terms containing r to the left, all other terms to the right

16r=48

r=48/16

r=3

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