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(2x-5)+(52)=(5x-16)
We move all terms to the left:
(2x-5)+(52)-((5x-16))=0
We get rid of parentheses
2x-((5x-16))-5+52=0
We calculate terms in parentheses: -((5x-16)), so:We add all the numbers together, and all the variables
(5x-16)
We get rid of parentheses
5x-16
Back to the equation:
-(5x-16)
2x-(5x-16)+47=0
We get rid of parentheses
2x-5x+16+47=0
We add all the numbers together, and all the variables
-3x+63=0
We move all terms containing x to the left, all other terms to the right
-3x=-63
x=-63/-3
x=+21
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