17/2x+8=34/4x+16

Solution for 17/2x+8=34/4x+16 equation:

17/2x+8=34/4x+16

We move all terms to the left:

17/2x+8-(34/4x+16)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+16)!=0

x∈R


We get rid of parentheses

17/2x-34/4x-16+8=0

We calculate fractions


68x/8x^2+(-68x)/8x^2-16+8=0

We add all the numbers together, and all the variables

68x/8x^2+(-68x)/8x^2-8=0

We multiply all the terms by the denominator


68x+(-68x)-8*8x^2=0

Wy multiply elements

-64x^2+68x+(-68x)=0

We get rid of parentheses

-64x^2+68x-68x=0

We add all the numbers together, and all the variables

-64x^2=0

a = -64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-64)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-128}=0$