(y+8)+(y+8)=(3y-27)

Solution for (y+8)+(y+8)=(3y-27) equation:

(y+8)+(y+8)=(3y-27)

We move all terms to the left:

(y+8)+(y+8)-((3y-27))=0

We get rid of parentheses

y+y-((3y-27))+8+8=0


We calculate terms in parentheses: -((3y-27)), so:

(3y-27)

We get rid of parentheses

3y-27

Back to the equation:

-(3y-27)


We add all the numbers together, and all the variables

2y-(3y-27)+16=0

We get rid of parentheses

2y-3y+27+16=0

We add all the numbers together, and all the variables

-1y+43=0

We move all terms containing y to the left, all other terms to the right

-y=-43

y=-43/-1

y=+43