-7(y+3)=8y-6

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Solution for -7(y+3)=8y-6 equation: 



-7(y+3)=8y-6

We move all terms to the left:

-7(y+3)-(8y-6)=0

We multiply parentheses

-7y-(8y-6)-21=0

We get rid of parentheses

-7y-8y+6-21=0

We add all the numbers together, and all the variables

-15y-15=0

We move all terms containing y to the left, all other terms to the right

-15y=15

y=15/-15

y=-1

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