8=-2(5v+3)+2(1+2v)

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Solution for 8=-2(5v+3)+2(1+2v) equation: 



8=-2(5v+3)+2(1+2v)

We move all terms to the left:

8-(-2(5v+3)+2(1+2v))=0

We add all the numbers together, and all the variables

-(-2(5v+3)+2(2v+1))+8=0



We calculate terms in parentheses: -(-2(5v+3)+2(2v+1)), so:

-2(5v+3)+2(2v+1)

We multiply parentheses

-10v+4v-6+2

We add all the numbers together, and all the variables

-6v-4

Back to the equation:

-(-6v-4)



We get rid of parentheses

6v+4+8=0

We add all the numbers together, and all the variables

6v+12=0

We move all terms containing v to the left, all other terms to the right

6v=-12

v=-12/6

v=-2

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