2(z+1)=5(z-2)

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Solution for 2(z+1)=5(z-2) equation: 



2(z+1)=5(z-2)

We move all terms to the left:

2(z+1)-(5(z-2))=0

We multiply parentheses

2z-(5(z-2))+2=0



We calculate terms in parentheses: -(5(z-2)), so:

5(z-2)

We multiply parentheses

5z-10

Back to the equation:

-(5z-10)



We get rid of parentheses

2z-5z+10+2=0

We add all the numbers together, and all the variables

-3z+12=0

We move all terms containing z to the left, all other terms to the right

-3z=-12

z=-12/-3

z=+4

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