-6x+28=3(x-4)+40

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Solution for -6x+28=3(x-4)+40 equation: 



-6x+28=3(x-4)+40

We move all terms to the left:

-6x+28-(3(x-4)+40)=0



We calculate terms in parentheses: -(3(x-4)+40), so:

3(x-4)+40

We multiply parentheses

3x-12+40

We add all the numbers together, and all the variables

3x+28

Back to the equation:

-(3x+28)



We get rid of parentheses

-6x-3x-28+28=0

We add all the numbers together, and all the variables

-9x=0

x=0/-9

x=0

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